3[z-(8z+33)+5]=2(z+4)

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Solution for 3[z-(8z+33)+5]=2(z+4) equation:


Simplifying
3[z + -1(8z + 33) + 5] = 2(z + 4)

Reorder the terms:
3[z + -1(33 + 8z) + 5] = 2(z + 4)
3[z + (33 * -1 + 8z * -1) + 5] = 2(z + 4)
3[z + (-33 + -8z) + 5] = 2(z + 4)

Reorder the terms:
3[-33 + 5 + z + -8z] = 2(z + 4)

Combine like terms: -33 + 5 = -28
3[-28 + z + -8z] = 2(z + 4)

Combine like terms: z + -8z = -7z
3[-28 + -7z] = 2(z + 4)
[-28 * 3 + -7z * 3] = 2(z + 4)
[-84 + -21z] = 2(z + 4)

Reorder the terms:
-84 + -21z = 2(4 + z)
-84 + -21z = (4 * 2 + z * 2)
-84 + -21z = (8 + 2z)

Solving
-84 + -21z = 8 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-84 + -21z + -2z = 8 + 2z + -2z

Combine like terms: -21z + -2z = -23z
-84 + -23z = 8 + 2z + -2z

Combine like terms: 2z + -2z = 0
-84 + -23z = 8 + 0
-84 + -23z = 8

Add '84' to each side of the equation.
-84 + 84 + -23z = 8 + 84

Combine like terms: -84 + 84 = 0
0 + -23z = 8 + 84
-23z = 8 + 84

Combine like terms: 8 + 84 = 92
-23z = 92

Divide each side by '-23'.
z = -4

Simplifying
z = -4

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